(4x^2)+100=0

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Solution for (4x^2)+100=0 equation: 



(4x^2)+100=0

a = 4; b = 0; c = +100;
Δ = b2-4ac
Δ = 02-4·4·100
Δ = -1600
Delta is less than zero, so there is no solution for the equation

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